Hi perl monks. I have an XML file as below, storing attributes of a list of files. 

<file>
<name>test.doc</name>
<userprop>
  <nameprop>Effective Date</nameprop> 
  <valueprop>16-Dec-2003</valueprop> 
</userprop>
<userprop>
  <nameprop>Owner</nameprop> 
  <valueprop>Adrian.Johnston</valueprop> 
</userprop>
<userprop>
  <nameprop>Version</nameprop> 
  <valueprop>v1.3</valueprop> 
</userprop>
</file>
<file>
...
</file>

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So if I would require all the files with version "v1.3", I would have to extract all "nameprop" nodes as below, and if the string is "Version", i'll get the equivalent string of valueprop and then do a comparison. 
my $nodeset = $xpath->find('//file/userprop/nameprop');
...
$valu_node = $xpath->find('../valueprop',$node)->get_node(1);

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However, if the XML for userprops was stored as attributes as below : 

<userprop name="Version">v1.3</userprop>

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Then, I could have taken easier XPath search of : 

my $nodeset = $xpath->find('//file/userprop/[@name='v1.3]');

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to derive all the version nodes. And then if they are "v1.3", I print out the file name. So qn is, is there any simple way to use XPath if my XML format is using sub-elements for "userprop", as in the first listing above. Thanks.

In reply to XPath search qn by Justudo

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