Regarding the concatenations, my implementation has several differences with respect to your original proposal:

Note: the neighbors of $n are $n+1, $n+1000, $n+1000000, etc., for a total of 13 neighbors (a cube is surrounded by 26 cubes, but you only need half of them to avoid counting twice)


In reply to Re: Re: Re: Re: Processing data with lot of math... by itub
in thread Processing data with lot of math... by qhayaal

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