Astonishingly, you are wrong about the character class. [^\w\s] matches characters that are neither words nor whitespace; i.e., punctuation: 
$_='o.ne<a>tw/o<b>';
@punks = /[^\w\s]/g;
print "<@punks>";

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yields 
<. < > / < >>

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The problem with my example was that I left the /g modifier off the pattern match. I've updated it, and tested it: 
while(<DATA>){
/http:\S*[^\w\s]/g and s/\G\n//;
print;
}
__DATA__
there is an http://whatever.com/address/
crossing/line/boundaries.html right in the
middle of this nice string.

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The PerlMonk tr/// Advocate

In reply to Re: Re: Regex to detect and remove a linebreak in an URL by Roy Johnson
in thread Regex to detect and remove a linebreak in an URL by Anonymous Monk

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