It is explicilty documented that hashes never, never, never have any meaningful order to them. So your "what you would expect" output is never going to be guarenteed to happen.

Now, for having each be localized . . . maybe. It might cause problems with tied hashes. I'll leave it to someone more familer with the internals.

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send money to your kernel via the boot loader.. This and more wisdom available from Markov Hardburn.

In reply to Re: Why Doesn't each() DWIM? by hardburn
in thread Why Doesn't each() DWIM? by enoch

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