Not all OP objects are the same size so do I have to be concerned that a 28 byte hole would have to accomodate a 56 byte op? Is there slack space built in?

Put the question in C terms. If you wanted 28 bytes to store a C struct and had an array of such structs in memory would you:

  1. Expect that these structs will be represented in memory by a contiguous array of 28 byte chunks
  2. Expect that just in case someone wanted to hand insert a 56 byte struct the programmer/compiler allocated 28 bytes + 28 spare??????

Now I don't know the real answer but I would be a little suprised if writing 56 bytes into a 28 byte hole did not overwrite the neighbouring 28 byte struct. Why have 28 and 56 byte structs if you always allocate 56 (which is what you are asking for)?

The only way I could see it working is if you replace the old object with a new object (less than or equal in size to the old) that points to a freshly allocated OP object in a free chunk of memory.

cheers

tachyon

In reply to Re: Moving an OP and replacing it by tachyon
in thread Moving an OP and replacing it by diotalevi

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