Maybe I am missing something here. Why should undef from a hash not overwrite a defined value? When I code something like

$value = $empty_hash{empty_value};

and $empty_hash{empty_value} has not been defined, $value will certainly get assigned undef since undef is the return value of the attemped hash reference. Or is it that a return value from a hash reference getting assigned is conditional upon the hash value being defined?
If I am wrong, please let me know because I have always thought otherwise.

davidj

In reply to Re^3: help with strict by davidj
in thread help with strict by jck

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