The //g modifier is tied to pos(), which is tied to the scalar being matched against. All matches on the same scalar with the g option read and set the same pos().

The ?? is more like a flip-flop, where the counter is attached to the expression itself, so separate ?? expressions each match once, even if they use the same pattern and/or match against the same scalar.

The PerlMonk tr/// Advocate

In reply to Re: Bizarreness in ?PATTERN? and g by Roy Johnson
in thread Bizarreness in ?PATTERN? and g by BUU

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