Hi all. japhy speaking. Here's the run-down:

• The regex variables are not reset or changed after a failed regex.
• The /g modifier, in scalar context, tells the regex to match once, and then update pos($str) to wherever the regex ended in the string. The next time that string is matched against by a regex with the /g flag, the regex will start looking NO SOONER than pos($str) in the string. pos() is not tied to a regex, it's tied to a string.
• A m?? regex matches only once (in between calls to reset()). That behavior is tied to THAT specific regex.
• Perl is compiled. That means /x/ for 1, 2; is different from /x/; /x/;.

Put it all together and you have this fact:

# code 1
$str = "abc";
for (1, 2, 3) {
  print $1 if $str =~ ?(.)?g;
}

# code 2
$str = "abc";
print $1 if $str =~ ?(.)?g;
print $1 if $str =~ ?(.)?g;
print $1 if $str =~ ?(.)?g;
[download]

The first code only prints 'a'. The second code prints 'abc'. This is because the first code has only one PMOP (Perl's internal representation of a pattern match operation), whereas the second code has THREE of them. Each PMOP has its own flags, such as the "I'm a m?? regex" flag.

Now for a bit of fun. What does this code print?

$str = "abc";
for (1, 2, 3) {
  $str =~ ?(.)?g;
  print $1;
}
[download]

Does it print "a" (and then two empty strings)? No. Why not? Because the regex variables ($1, et. al.) are in a *slightly* larger scope than you'd expect: they retain their values for the duration of that for loop. It would be similar to saying:

$str = "abc";
{
  local ($_1, $_2, ...);
  for (1, 2, 3) {
    $str =~ ?(.)?g and ($_1, $_2, ...) = ($1, $2, ...);
    print $_1;
  }
}
[download]

except, of course, that you don't have to.

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