What's wrong with a Perl block? grep takes a block. Here's the answer: 
sub x(&) {
    my $coderef = shift;

    use Data::Dumper; print Data::Dumper->Dump([$coderef],['coderef'])
+;

    {
    $_ = 'bumpkin';

    $coderef->();
    }
}

x { print "$_.YYY" };

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In reply to RE: Re (tilly) 1: passing and processing code references by princepawn
in thread passing and processing code references by Anonymous Monk

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