Is it possible to assign a value to a variable and then do a substitution on it in a single statement? For example suppose I want to start with a URL, remove a known host-domain name, then assign the remaining dir/filename to a variable. With two statements you could say 
$dirfilename = $url;
$dirfilename = s|http://foo.bar.com/||;

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But is there a way to do the same thing in one statement? 
$dirfilename = $url =~ s|http://foo.bar.com/||;

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will not work because this does the substitution on $url then assigns a 1 to $dirfilename to indicate the successful substitution.

Many thanks....

Steve

In reply to Assign & substitute in one statement? by cormanaz

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