the $?>>8 construct shifts the $? value to the right by 8 bits. In order to examine the entire value, don't bit-shift it. However, perldoc perlvar has this to say about $?:
This is just the 16-bit status word returned by the wait() system call (or else is made up to look like it).
Where I come from, 16-bit values equate to 2-byte values, not four.

thor

In reply to Re: Getting the errorlevel from a system call by thor
in thread Getting the errorlevel from a system call by Anonymous Monk

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