perlfaq4 suggests:
@union = @intersection = @difference = ();
    %count = ();
    foreach $element (@array1, @array2) { $count{$element}++ }
    foreach $element (keys %count) {
        push @union, $element;
        push @{ $count{$element} > 1 ? \@intersection : \@difference }
+, $element;
    }

[download]
Based on that you could: 
sub intersection{
 my(%count,@res);
 for(map @$_,@_){$count{$_}++}
 for(keys %count){push @res,$_ if $count{$_}==@_}
 @res;
}
@a=intersection(\@b,\@c,\@d);

[download]

In reply to Re: intersection of N arrays by Ido
in thread intersection of N arrays by basscakes

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