For small numbers, this should be straightforward ...

@divisors = grep { $number % $_ == 0 } 1 .. $number;

[download]

I would not worry about optimizing this, unless you need it for very many or very big numbers ... but then it would be something like this:

# First, the lower half of the divisors:
@divisors = grep { $number % $_ == 0 } 1 .. sqrt($number);
# Then, the upper half:
push @divisors, map {$number == $_*$_ ? () : $number/$_} reverse @divi
+sors;

[download]

(Sorry, I missed the Math::BigInt stuff ... but I guess the algorithm above can be adapted to that case as well?)

Update: Most of my code could benefit from comments. I added comments to the optimized version. Never code as if the guy who ends up maintaining your code can always maintain a proper caffeine intake.

print "Just another Perl ${\(trickster and hacker)},"
The Sidhekin proves Sidhe did it!

In reply to Re: Finding all divisors of an integer by Sidhekin
in thread Finding all divisors of an integer by chiburashka

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