Sidhekin,
I would not worry about optimizing this, unless you need it for very many or very big numbers
Indeed, the node was updated after you (and I) already started posting. I would say that you only need to go to $number / 2 though.

@divisors = grep { $number % $_ == 0 } 1 .. sqrt($number);
I think you are thinking of prime factorization here. You can stop there to determine primeness but not to determine all factors.

Cheers - L~R

People should not be allowed to touch keyboards early in the morning (weekend) without proper caffeine intake. I completely missed the push in the second line of code

In reply to Re^2: Finding all divisors of an integer by Limbic~Region
in thread Finding all divisors of an integer by chiburashka

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