$VAR1 = 'three'; $VAR2 = undef; $VAR3 = 'one'; $VAR4 = undef; $VAR5 = 'two'; $VAR6 = undef;
CountZero
"If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law
In reply to Re^4: hash problem
by CountZero
in thread hash problem
by m.y
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