I am not sure I understand your point. I think you are trying to say that 

$class = ref($class) || $class;

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is no better/worse than 
my $class = shift;
bless {}, $class;

[download]
which is quite true, and since that is also a common idiom which will produce the same issue, then maybe that is not so good either.

In all cases, $class is undef, and when bless is passed undef it blesses into main. It might (and I stress might, because I am not so sure of this) make sense if when bless encountered undef in its second argument, that it treated it as a one-argument bless instead (which would result in blessing into the current package).

-stvn

In reply to Re^2: Is "ref($class) || $class" a bad thing? by stvn
in thread Is "ref($class) || $class" a bad thing? by stvn

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