japhy,
Here is the mathematical formula with a little help from google. 
(N+5) (N+4) (N+3) (N+2) (N+1) / 120

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If I were solving the problem using code and I couldn't figure out how to use one of those nifty CPAN modules, I would do it the inefficient way (sort, join, use a hash).

Cheers - L~R

In reply to Re: unordered sets of N elements by Limbic~Region
in thread unordered sets of N elements by japhy

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