print (...) interpreted as function...
possible solutions: 
print ((sort(<*>))[-1]), "\n";
# or
print+(sort(<*>))[-1], "\n";

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see also print (...) interpreted as function

He who asks will be a fool for five minutes, but he who doesn't ask will remain a fool for life.

Chady | http://chady.net/

In reply to Re^3: What's the difference between stat and sort? by Chady
in thread What's the difference between stat and sort? by PetaMem

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