Actually chomp typically eats \n only which is the line feed char LF not the carriage return char CR....
printf "CR \\r \\%03o 0x%02x\n", ord("\r"), ord("\r");;
printf "LF \\n \\%03o 0x%02x\n\n", ord("\n"), ord("\n");;
my $str = "str\015\012";
for( 1..2 ) {
print "string '$str'\n";
print "length ", length $str, "\n";
chomp $str;
print "string '$str'\n";
print "length ", length $str, "\n\n";
}
Technically chomp removes any trailing string that corresponds to the current value of $/ (also known as $INPUT_RECORD_SEPARATOR in the English module).
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