ok here i go i have the following code! 
@files = <../data/texts/*.txt>;

print start_form(-action=>"index.pl");
   print p( {-align=>'center'}, font( {-size=>5, -color=>'Lime'}, 'Λόγ
+ος Ψυχωφελής και Θαυμάσιος ---> ' ),
                                popup_menu( -name=>'choice', -values=>
+\@files ),
                                submit('ok'));
print end_form(), br();


if ( $file = param("choice") )
{
   open(FH, "$file") or die $!;
      @data = <FH>;
   close(FH);

   $data = join("", @data);
}

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I want the arrray @files = <../data/texts/*.txt>; who gives filanes like this ../data/texts/file1.txt to conever its values to file, file2,file3 and so on. to remove the path and the .ext that is.

Why? because i want to display the arrays values to a popup menu without the path and the extension.

Then before this line open(FH, "$file") or die $!; o want the array to be re-converted to its origianl state so that the file could actually open. This rquires s/// operator in my opinion but i dont knwo how to write it. Thanks!
The Devil Is In The Details!

In reply to Array values reformation by Nik

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