You don't need to make it quoted. The "argv" of ls is identical on the two shell command invocations. The shell ignores the quotes, because there wasn't any whitespace in the filename word.

If you want to show two different shell lines, then hand the command to the shell, using a single-arg invocation for system:

for my $quote (q{}, q{"}) { $cmd = "ls -l ${quote}simple.pl${quote}"; warn $cmd; system $cmd;
However, I would not recommend doing this in production code. This is just a demo.

The real question I have is "what are you trying to do, and why do you care about the quotes?".

-- Randal L. Schwartz, Perl hacker


In reply to Re: Quoting arguments to system by merlyn
in thread Quoting arguments to system by princepawn

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