You're losing some values because you're overwriting them before they get dealt with. The first key processed overwrites the value of $hash{0}. You could put the 'ordered' info into a different hash, and this wouldnt happen anymore.

Also, sort by default is a string comparison sort, so it goes like 1,10,11,12,13,14,15,16,17,18,19,2,20, etc, and negaitve values would come before the positive. Run this bit of code: 

    foreach my $i (sort (-20 .. 20)) {
        print "$i\n";
    }

[download]
To do a numeric sort, you need 
    sort {$a <=> $b} (keys %hashone)

[download]
In the end, i'd still agree with ovid about what you're doing!

In reply to Re: re-key a hash by shemp
in thread re-key a hash by Anonymous Monk

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