You shouldn't do what you're trying to do. Using variable substitution like that is slow, it's ugly, and it could be actively dangereous.

What you should do instead is use the param method of CGI - like this:

$input=new CGI;
print param('custtype')." ".param($xx);

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In reply to Re: Variable Substitution within NameSpace by matija
in thread Variable Substitution within NameSpace by yellow_tree_frog

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