ishnid beat me to it, so here's a nifty "simplification":

$bar =~ s/varchar\s*\((\d+)(??{$1<256})\)/TEXT/i;

[download]

update: I suppose it would be helpful to regex novices to give an explanation of the above:

The (??{ code }) construct (note: see the warning about this in perlre) evaluates the code inside the brackets, and treats the results as if it were part of the regex. If the number captured by (\d+) is less than 256, it returns a 1. The parser then tries to match on that 1 and fails, since the \d+ already sucked up all the digits.

If the number is 256 or greater, the expression returns a blank string (not 0), so the regex matches.

See perlre and perlretut for all the gory details.

Brad

In reply to Re: String replacement with regex... by bgreenlee
in thread String replacement with regex... by amonotod

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