If I call a script from the command line as follows: 
perl process.pl input.txt > output.txt

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...the name of the perl script being executed is in $0 and the name of the input file can be easily extracted from @ARGV. But is there any way of getting at the output filename? E.g. 
while (<>) {
    print "Reading from: $ARGV, Writing to: $???\n";
}

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I understand that under normal circumstances it is not possible to extract a filename from a filehandle - but if the name is being passed via the command line as here, is there (or should there be?) a convenient way of retrieving it?

janitored by ybiC: Retitle from "Missing special variable?" for searchability

In reply to Get filename of STDOUT by Anonymous Monk

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