Well, it's highly non-portable, but on linux, you can find this by looking on the proc filesystem and traversing a symlink. You can find the file name of the file to which STDOUT is attached by readlink "/proc/$$/fd/1";. Demonstrated as: 
[me@host]$ perl -le 'my $outputfile = readlink "/proc/$$/fd/1"; print 
+STDERR $outputfile;' > t1
/home/me/t1
[me@host]$

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That is... look into this process (/proc/$$), examine its filehandles (/proc/$$/fd). In particular, look at its filehandle number 1 (the fileno of STDOUT). This will be a symlink to the actual file that STDOUT is opened to (hence the readlink). 
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:Wq
Not an editor command: Wq

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In reply to Re: Missing special variable? by etcshadow
in thread Get filename of STDOUT by Anonymous Monk

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