Sure, if k1 is much smaller than k2, O( k1 n ) will be smaller for small values of n than O( k2 log n ). Using builtins is a good way of getting very small values for k1, and I've asserted many times that this is a sensible optimization goal in Perl, even recently.

But with n growing, the constants eventually become irrelevant. Since BrowserUk claims to be unable to hold all of his data in memory, I would assume this is such a situation. Even Perl's builtin splice won't move 100,000 elements down one position faster than spelled-out Perl code would swap 17 (≅ log2 100_000) elements.

Makeshifts last the longest.

In reply to Re^9: Re-orderable keyed access structure? by Aristotle
in thread Re-orderable keyed access structure? by BrowserUk

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