$result = $obj->functionA($obj->functionB());

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That's going to be calling method functionB in a list context. Therefore, the one and only answer you can have in Perl is "it is returning a list". Every other thing you think it might be doing is not happening.

Your statement of "always going to return a list" is therefore true. Your statement of "going to be a hash" is therefore always false.

I don't see the confusion here. It's the caller that decides what the called routine returns. It's that simple.

-- Randal L. Schwartz, Perl hacker
Be sure to read my standard disclaimer if this is a reply.

In reply to •Re^3: Auto-detecting returned or passed variable type by merlyn
in thread Auto-detecting returned or passed variable type by richard5mith

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