The following code produces some bizzare output. Apparently, "a"++ = "b", and "z"++ = "aa". But if I ever try to convert $string to a number "$number = (int $string)" I get 0. Anybody know why? --snip!-- 
#!/usr/bin/perl

my $string = "a";

for( $i = 0; $i < 64; $i++ ) {
    $string++;
    print "string = '$string'\n";
}

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--snip!--

Originally posted as a Categorized Question.

In reply to Why does $string++ work the way it does? by spaz

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