There are probably many ways to do this. Chances are
there is some whizzy one-liner using Quantum::Superpositions or some such - but I haven't had time to look.
There are 2n-1 possibilities (where n is the length of your input array) and that suggested (to me) looking at the binary digits of each number from 1 to 2n-1. That's what this solution does. It probably isn't the most elegant, and I suspect it is not the most efficient either.
use strict;
use Data::Dumper;
my @firstArray = ( "item1", "item2", "item3" );
my $n = @firstArray;
my @results;
for my $i (1..2**$n-1) {
my @selection;
for my $j (0..$n-1) {
if ($i & 2**$j) {
push @selection, $firstArray[$j];
}
}
push @results, \@selection;
}
print Dumper(\@results);
s^^unp(;75N=&9I<V@`ack(u,^;s|\(.+\`|"$`$'\"$&\"\)"|ee;/m.+h/&&print$&
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