Hello

I read this great article about Perl Command-Line Options, printed it and had it on my desk. Today I needed to accomplish a simple task: having the output of an ls -1 (that's "minus one") and output a single line with all the filenames separated by ":". In other days I would have written it this way:

ls -1 | perl -e '@_=<>;chomp@_;print join":",@_'

and in fact it just works. But after reading the article, and in particular this:

Using -l and giving it no value has two effects. Firstly, it automatically chomps the input record, and secondly, it sets $\ equal to $/. If you give -l an octal number (and unlike -0 it doesn't accept hex numbers) it sets $\ to the character represented by that number and also turns on auto-chomping.

I expected I could write my one-liner this way:

ls -1 | perl -le 'print join ":",<>'

but it actually doesn't what I expected. Could anybody explain where I am doing wrong?

Thanks a lot

Ciao!
--bronto

The very nature of Perl to be like natural language--inconsistant and full of dwim and special cases--makes it impossible to know it all without simply memorizing the documentation (which is not complete or totally correct anyway).
--John M. Dlugosz

In reply to perl one-liner doesn't autochomp input by bronto

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