ikegami provided a very good answer for why your original regexp didn't return the captures you were hoping for, and he provided a good m//g solution. But I wanted to point out yet another way to do it, using the experimental (?{...code...}) construct, and as you requested, a single regular expression. ;) 

use strict;
use warnings;

use vars qw/@array/;

$_ = "This is list number 12. It contains apples, pears, peaches. Tota
+l cost is 5.";

if ( 
    m/contains\s+
      (?:(\w+)(?{push @array, $^N}),\s+)*
      (?:(\w+)(?{push @array, $^N})\.\s+\b)
    /x
) {
    print "@array\n";
}

[download]

I used the /x modifier to break the regexp into smaller chunks so you could see more clearly what's going on. The special variable $^N contains the most recent capture within the regexp. So even though $1 only contains the last match in the first set of parens, if you check at the proper point in time, it (and $^N) will contain that first capture too. Be sure to read up in perlre for details. This is a tricky subject, but kind of fun, IMHO.


Dave

In reply to Re: Regex to extract multiple occurrences by davido
in thread Regex to extract multiple occurrences by Crackers2

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