update : taken into account davorg's remarks.

Internally, a hash table can be thought of a sort a "special" list. That means the following hash 
%hash = ('test' => '24',
         'blah' => '253');

[download]
can be equivalent to 
@hash = ('test', '24', 'blah', '253');

[download]

BTW, => is equivalent to , here.

So if you understand that a hash is a special representation for an list, then you expression does the following :
That is, you convert an hash to a array using the references.

HTH

--
zejames

In reply to Re: doubts in reference by zejames
in thread doubts in references by prasadbabu

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