I guess I am way too new to this... can someone tell me where I can find an answer to my answer. I read the following:

Perl computes only with double-precision floating-point values.[2] This means that there are no integer values internal to Perl; an integer constant in the program is treated as the equivalent floating-point value.[3] You probably won't notice the conversion (or care much), but you should stop looking for integer operations (as opposed to floating-point operations), because there aren't any.

[2] A "double-precision floating-point value" is whatever the C compiler that compiled Perl used for a double declaration.

[3] Unless you use "integer mode," but that's not on by default.

And I am trying to wrap my little brain around numbers/scalar data but this is not working... Please. Thanks for the patience - newbie

Janitored by davido: Added formatting to match user's input, and used code tags to prevent square brackets from being interpreted as links.

20040928 Edit by []: Changed title from 'Don't understand, what this means'

In reply to Confusion Regarding Perl's Numerical Handling by Anonymous Monk

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