Hi, I typed: 
perl -e '%h = ( q => 2, w => 2 ); print reverse %h = reverse %h'

[download]
and wonder why I get three values back 'w22' I expect 'q2' or 'w2' at perls option. More testing shows even more wired results. In the example below, I expect %x reversed in %h but it is not. There was not even a 'a' => 2 pair in the original %h. 
perl -MData::Dumper -le '%h = (1 => 2, a=>"b", c => 2); %h = reverse (
+ %x = reverse %h); print Dumper({x => \%x, h =>\%h});'
__OUTPUT__
$VAR1 = {
          'x' => {
                   'b' => 'a',
                   '2' => 'c'
                 },
          'h' => {
                   'a' => 2,
                   'c' => 2
                 }
        };

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Perl 5.8.4 cofuses me even more 
perl5.8.4 -MData::Dumper -le '%h = (1 => 2, a=>"b", c => 2); %h = reve
+rse ( %x = reverse %h); print Dumper({x => \%x, h =>\%h});'
__OUTPUT__
$VAR1 = {
          'x' => {
                   'b' => 'a',
                   '2' => 'c'
                 },
          'h' => {
                   '' => 2
                 }
        };

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can you explain this behavior please?
UPDATE: I really expect to lose the dupes. My point is that I expect that %h is a reverse of %x. But it is not for me, tested on
Mac OSX and Linux. So I really wonder that you get different output.
Boris

In reply to whats wrong reverse %x = reverse %h? by borisz

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