You have an error in using numeric '==' instead of alpha 'eq'.

You appear to have an implicit rule for generating a couple of other elements from one. My best guess is that the prefix character is kept, the number formed by digits up to the colon is doubled or zero, and one is subtracted from the trailing number. From a sample of one, it's hard to tell if you mean something else.

Your algotrithm seems to be necessarily quadratic, but it might be reduced if we knew what you were trying to do. Here's how I'd do it. Once you have $element, you can use the rule to calculate a pair of matching strings, then grep the array for matches. I'll put results into a hash of arrays, not knowing what else to do with them. 

my %hash;
for my $element (@array) {
    my ($prefix, $first, $second) =
        $element =~ /^([A-Z])(\d+):(\d+)$/;
    my @matches = ( $prefix . '0:' . $second - 1,
                    $prefix . $first * 2 . ':' . $second - 1);
    $hsh{$element} = [ grep {
            $_ eq $matches[0] or $_ eq $matches[1]
        } @array ];
}

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After Compline,
Zaxo

In reply to Re: recursive array search by Zaxo
in thread recursive array search by state-o-dis-array

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