This is wrong. Very wrong. Testing each value against every other value in the other hash? So, for hashes with n keys, you're going to have at least (n-1)^2 cases where $v1 ne $v2 - and that's if they match. NAME may not match EMP_NAME, but it definitely won't match EMP_PHONE, EMP_AGE etc, so why test it?

Only n matches need to be made - assuming you can map the keys across the hashes correctly (my guess is below on this one).

I think you misunderstood the question.

cLive ;-)

In reply to Re^2: Comparing hash data by cLive ;-)
in thread Comparing hash data by FubarPA

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