my %hash1; my %hash2 = (1 => 2, 3 => 5, 4 => 2,); my @keys = keys %hash2; for (my $i=0; $i<@keys; $i++) { $hash1{"$keys[$i]-$keys[$i]"}=$hash2{$keys[$i]}; for (my $j=$i+1; $j<@keys; $j++) { $hash1{"$keys[$i]-$keys[$j]"} = $hash2{$keys[$i]}*$hash2{$keys +[$j]}; } }
In reply to Re: Self-Looping over hash - how to remove duplicate
by Anonymous Monk
in thread Self-Looping over hash - how to remove duplicate
by monkfan
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