I may have misunderstood this, but with $n = 19 and $m = 3, fix gives 21 which is not an even multiple of 3.

Why not just use $m * $n * 2 ?

In reply to Re^3: Best way to make sure a number is an even multiple of another? by Arunbear
in thread Best way to make sure a number is an even multiple of another? by demerphq

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