And to get things going, I'll post the bad solution that everyone should be able to beat. This ignores all but the first 3 pegs. 
#! /usr/bin/perl -w
use strict;

my $disk_count = pop;
solve('A'..'C', reverse 1..$disk_count);

sub solve {
  my ($peg_from, $peg_to, $peg_hold, $first_disk, @rest) = @_;
  return unless $first_disk;
  solve($peg_from, $peg_hold, $peg_to, @rest);
  print "$first_disk: $peg_from -> $peg_to\n";
  solve($peg_hold, $peg_to, $peg_from, @rest);
}

[download]
Again, this makes no use of extra pegs, which you can use to beat it.

In reply to Re: Hanoi Challenge by tilly
in thread Hanoi Challenge by tilly

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