Another possible problem is that the OP uses the table alias C, but never defines it anywhere that I can see (no pun intended.) Perhaps what was meant was:

$sql= "SELECT C.mast1, C.mast2 FROM MASTER AS C WHERE C.mast1=? AND C.mast2=?";

-Yendor

IWeThey
HOPE Ride

In reply to Re^2: Value to Sub by Yendor
in thread Value to Sub by Anonymous Monk

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