Important thing I overlooked: your solution modifies $sBegin!

You would need to create a copy before modifying. One way: 

($sEnd) = map {s/hello/goodbye/g; $_;} map {$_} ($sBegin);

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Another: 
($sEnd) = map {s/hello/goodbye/g; $_;} @{[$sBegin]};

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A functionally similar solution that doesn't use map: 
$sEnd = do {local $_ = $sBegin; s/hello/goodbye/g; $_;};

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Of course, creating a copy and working on it is the canonical solution: 
(my $sEnd = $sBegin) =~ s/hello/goodbye/g;

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This couldn't be used in a combination declaration-assignment, though, while the others could.
Caution: Contents may have been coded under pressure.

In reply to Re: Answer: How do I assign & substitute in one statement? by Roy Johnson
in thread How do I assign & substitute in one statement? by dfaure

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