Don't see how your regex could do what you say. Your "^(\d)$" is looking for a SINGLE digit between start of record/string, "^," and the end of same, "$."
What follows sorta' does what you're talking about altho in the regex you'll need to do "(012346" rather than "(\d{6}" or some variant of (any digit except 5,7, 8 or 9) or similarly clunky approaches to deal with the exact string
and, is this homework? If so, it's a good idea to mention ('fess up) that fact, so monks can teach without actually DOING the homework.
note that the last 6 items in data do NOT match the regex.#!C:/perl/bin -w use strict; use vars qw ($input @input @img $img); @input = <DATA> ; foreach $input (@input) { if ( $input =~ # Caret in next line: Start at begining of +string/record/whatever /^(\d{6} # sTART CAPTURE, with any digit, [0-9] +, exactly six times. (- # optionally (trailing "?") in a NON +-capture-group: a dash followed by a \w{3})? # word char, exactly 3 times; end group +ing parens \.jpg$ # literal period followed by "jpg" endin +g the string ) # end capture /ix ) { #case insensitive (to catch -all and - +EXP); extended form push(@img, $input); } } print "\n\t+++++\n"; print @img; print "\n\tdone\n"; exit; __DATA__ 012346.jpg 012346-all.jpg 012346-EXP.jpg 012346-exp.jpg 012346-ALL.jpg 012345.jpg 12345.jpg 01234.jpeg 0123345+ALL.jpg 0123345-exp.jpg 0123345-ALL.jpg not_jpg.last
In reply to Re: regex help
by ww
in thread regex help
by calypso
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