You can still squeeze three more characters:
(I played with the option of wasting half the random numbers, but it seems it's not really useful...) 

#!/usr/bin/perl -l
$N=pop;print 1/$N*grep{%h=map{int rand 10}1..$ARGV[0]*2;9<keys%h}1..$N

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In reply to Re^3: Golf: Pandigital puzzle by itub
in thread Golf: Pandigital puzzle by itub

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