you're calling print with no arguments, which means it defaults to printing the contents of $_, which happen to be (in this case), the number '1'.

No, that's not right. Notice the ; is commented out too, so the statement does not end on that line. It's actually what Your Mother said -- the return value from closedir.

In reply to Re^2: CGI throws in an extra character. Why? by Anonymous Monk
in thread CGI throws in an extra character. Why? by Petras

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