Because floating point is not exact (again)

$n=0;
print ($n,"\n");
while ($n<1){
    $n=$n+.1;
    printf ("%0.18f \n", $n);
}

[download]
0
0.100000000000000006 
0.200000000000000011 
0.300000000000000044 
0.400000000000000022 
0.500000000000000000 
0.599999999999999978 
0.699999999999999956 
0.799999999999999933 
0.899999999999999911 
0.999999999999999889 
1.099999999999999867

[download]

Each time you make a floating point addition, you are accumulating error.

In reply to Re: non-integer increments by fglock
in thread non-integer increments by spiccioni

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