A bit confused here. The string "(\\.)" isn't the same as the regexen in the other two examples. Because stringification removes a level of backslashes, so the regex applied in the second example is really (\.) which is, of course, very different from (\\.)

I think the backslash obscures the issue a lot, though, so I added another test without any backslashes: $s =~ "(a.c)" and print $1;

It produced abc which seems to me to indicate that the string is actually being evaluated as a regex. And I think you're saying that this isn't the case.

So what am I missing? Or misinterpreting?

In reply to Re^2: Naked quotes work like m//? by Nkuvu
in thread Naked quotes work like m//? by samtregar

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