Maybe I wasn't clear. This means that 
(abc)(b-ac)

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and 
(cb-a)(bca)

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are equally correct input strings (they are even the same expression since (a AND b AND c) OR (b AND NOT a AND c) is the same as (c AND b AND NOT a) OR (b AND c AND a)).

But the output of the first reduction would be 

(bc)

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and of the second reduction 
(cb)

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Of course there can be many negated variables like this: 
(-a-b-c-d)(-c-da-b)

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which would result in 
(-b-c-d)

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In reply to RE: Re: Boolean algebra by le
in thread Boolean algebra by le

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