Monks; I have a scalar containing text with a mixture of line ending characters (it's Lotus Notes e-mail message text). I want to replace all of the LFs to be CRLFs.
I have tried many different regexp approaches. Below is the relevant snippet: 
  open (TEXTFILE, ">$subdir/message.txt")
     or die "Can't create $subdir message file: $!";
  print TEXTFILE "From: ", $doc->{From}->[0];
  print TEXTFILE "Subject: ", $doc->{Subject}->[0];
  $doc->{Body} =~ s/\015/\n/gm;
  print TEXTFILE $doc->{Body};
  close TEXTFILE;

[download]
$doc->{Body} contains the text with the mixture of LFs & CRLFs. This is a WinDoze app so I'm sure print is putting CRLFs on the line ends.
In the s/ I've tried everything I can think of: \x0D instead of \015 s instead of m at the end, etc. I still end up with extranneous LFs left. I think it's a problem of my understanding of the concept of a line in a regexp or something.

Doug

***Update*** here's how I finally got it to work. 
  open (TEXTFILE, ">$subdir/message.txt")
     or die "Can't create $subdir message file: $!";
  print TEXTFILE "From: ", $doc->{From}->[0];
  print TEXTFILE "Subject: ", $doc->{Subject}->[0];
  my $NewBody = $doc->{Body};
  $NewBody =~ s/\x0D\n/\n/g;
  print TEXTFILE $NewBody;
  close TEXTFILE;

[download]
The problem was that I was trying to modify a Lotus Notes Object. Kudos to diotalevi for that tip.

Doug Doug

In reply to regexp for scalar containing a mixture of LF & CRLF by NateTut

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