Update: Fixed. As Jenda observed, my original solution solved a problem other than the one presented.

O(N*log(N) + N*(M + M3) + M)
= O(N*log(N) + N*M3)
N = number of words.
M = length of words.

Don't let the M3 scare you. Benchmark them to find out which is best for you.

use strict; use warnings; my @data = qw/a mnk ab m b bc abcd cd bcd bd m nk /; @data = sort { length($a) <=> length($b) } @data; my %result; foreach my $word (@data) { my $uc_word = uc($word); my $partial_word; foreach my $start_letter (1..length($uc_word)) { foreach my $num_letters ($start_letter..length($uc_word)-$start_ +letter+1) { delete($result{substr($uc_word, $start_letter-1, $num_letters +)}); } } $result{$uc_word} = $word; } print join(",", values(%result));

In reply to Re: Seeking the longest string in an array by ikegami
in thread Seeking the longest string in an array by johnnywang

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